f(x+1)=4x^2+3x-4

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Solution for f(x+1)=4x^2+3x-4 equation: 


Simplifying
f(x + 1) = 4x2 + 3x + -4

Reorder the terms:
f(1 + x) = 4x2 + 3x + -4
(1 * f + x * f) = 4x2 + 3x + -4
(1f + fx) = 4x2 + 3x + -4

Reorder the terms:
1f + fx = -4 + 3x + 4x2

Solving
1f + fx = -4 + 3x + 4x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
4 + 1f + fx + -3x + -4x2 = -4 + 3x + 4x2 + 4 + -3x + -4x2

Reorder the terms:
4 + 1f + fx + -3x + -4x2 = -4 + 4 + 3x + -3x + 4x2 + -4x2

Combine like terms: -4 + 4 = 0
4 + 1f + fx + -3x + -4x2 = 0 + 3x + -3x + 4x2 + -4x2
4 + 1f + fx + -3x + -4x2 = 3x + -3x + 4x2 + -4x2

Combine like terms: 3x + -3x = 0
4 + 1f + fx + -3x + -4x2 = 0 + 4x2 + -4x2
4 + 1f + fx + -3x + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
4 + 1f + fx + -3x + -4x2 = 0

The solution to this equation could not be determined.

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